Alejandro Davidovich Fokina vs Alexander Zverev Head to Head Tennis Stats and Match Analysis

Alejandro Davidovich Fokina and Alexander Zverev have met 7 times in professional competition, with Alexander Zverev leading 6-1. Their most recent encounter was in October 2025 at Paris, where Alexander Zverev prevailed on hard court 6-2 6-4.

Alejandro Davidovich Fokina: Against top 10 players in the last 52 weeks, Alejandro Davidovich Fokina holds a 2-4 record (33.3%). Throughout his career, he has competed against top 10 47 times, winning 12 (25.5%). Over the past 10 matches, he holds a 5-5 record. Over the past 52 weeks, Alejandro Davidovich Fokina has posted a 36-25 record (59.0% win rate). Over his career at ATP level, Alejandro Davidovich Fokina holds a record of 102-89 (53.4%) on hard, 54-48 (52.9%) on clay, and 13-14 (48.1%) on grass. In the last 52 weeks: 25-17 (59.5%) on hard, 7-4 (63.6%) on grass, and 4-4 (50.0%) on clay at ATP level. Alejandro Davidovich Fokina has won three titles at Challenger/ITF level (two on hard and one on clay). Alejandro Davidovich Fokina is currently serving 4.0 aces per match in the last 52 weeks (61 matches), up from a career average of 3.0.

Alexander Zverev: Against top 50 players in the last 52 weeks, Alexander Zverev holds a 42-17 record (71.2%). Throughout his career, he has competed against top 50 453 times, winning 288 (63.6%). Over the past 10 matches, he holds a 9-1 record. Over the past 52 weeks, Alexander Zverev has posted a 63-21 record (75.0% win rate). Over his career at ATP level, Alexander Zverev holds a record of 287-125 (69.7%) on hard, 182-64 (74.0%) on clay, and 48-24 (66.7%) on grass. In the last 52 weeks: 35-14 (71.4%) on hard, 20-4 (83.3%) on clay, and 6-3 (66.7%) on grass at ATP level. Alexander Zverev has won 21 ATP tour-level titles (11 on hard and 10 on clay), including one Grand Slam title (on clay). He has also won an Olympic gold medal. Alexander Zverev serves an average of 8.5 aces per match in the last 52 weeks, consistent with his career average of 8.2.