Alexander Zverev vs Tallon Griekspoor Head to Head Tennis Stats and Match Analysis

Alexander Zverev and Tallon Griekspoor have met 11 times in professional competition, with Alexander Zverev leading 9-2. Their most recent encounter was in January 2026 at United Cup, where Alexander Zverev prevailed on hard court 7-5 6-0.

Alexander Zverev: Against top 50 players in the last 52 weeks, Alexander Zverev holds a 35-19 record (64.8%). Throughout his career, he has competed against top 50 442 times, winning 277 (62.7%). Over the past 10 matches, he holds a 6-4 record. Over the past 52 weeks, Alexander Zverev has posted a 55-24 record (69.6% win rate). Over his career at ATP level, Alexander Zverev holds a record of 285-129 (68.8%) on hard, 162-60 (73.0%) on clay, and 45-23 (66.2%) on grass. In the last 52 weeks: 29-14 (67.4%) on hard, 18-7 (72.0%) on clay, and 6-3 (66.7%) on grass at ATP level. Alexander Zverev has won 22 ATP tour-level titles (13 on hard and nine on clay). He has also won an Olympic gold medal. Alexander Zverev is currently serving 7.3 aces per match in the last 52 weeks (79 matches), down from a career average of 8.1.

Tallon Griekspoor: Against top 10 players in the last 52 weeks, Tallon Griekspoor holds a 3-4 record (42.9%). Throughout his career, he has competed against top 10 37 times, winning 6 (16.2%). Tallon Griekspoor has lost his last 4 matches. Over the past 10 matches, he holds a 4-6 record. Over the past 52 weeks, Tallon Griekspoor has posted a 32-27 record (54.2% win rate). Over his career at ATP level, Tallon Griekspoor holds a record of 66-69 (48.9%) on hard, 26-27 (49.1%) on clay, and 20-12 (62.5%) on grass. In the last 52 weeks: 15-18 (45.5%) on hard, 11-7 (61.1%) on clay, and 4-1 (80.0%) on grass at ATP level. Tallon Griekspoor has won three ATP tour-level titles (two on grass and one on hard). He has also won 18 titles at Challenger/ITF level (10 on clay and eight on hard). Tallon Griekspoor is currently serving 8.3 aces per match in the last 52 weeks (59 matches), up from a career average of 6.8.