Alexandra Eala vs Katerina Siniakova Head to Head Tennis Stats and Match Analysis

Alexandra Eala and Katerina Siniakova have met 1 time in professional competition, with Katerina Siniakova leading 1-0. Their most recent encounter was in October 2024 at Wuhan, where Katerina Siniakova prevailed on hard court 6-3 6-1.

Alexandra Eala: Against top 50 players in the last 52 weeks, Alexandra Eala holds a 13-15 record (46.4%). Throughout her career, she has competed against top 50 42 times, winning 17 (40.5%). Over the past 10 matches, she holds a 8-2 record. Over the past 52 weeks, Alexandra Eala has posted a 47-28 record (62.7% win rate). Over her career at WTA level, Alexandra Eala holds a record of 20-25 (44.4%) on hard, 8-5 (61.5%) on grass, and 7-12 (36.8%) on clay. At Challenger/ITF level: 140-62 (69.3%) on hard, 9-3 (75.0%) on grass, and 8-12 (40.0%) on clay. In the last 52 weeks: 16-13 (55.2%) on hard, 8-5 (61.5%) on grass, and 4-6 (40.0%) on clay at WTA level. 12-3 (80.0%) on hard and 5-0 on grass at Challenger/ITF level. Alexandra Eala has won six titles at Challenger/ITF level (five on hard and one on grass). Alexandra Eala serves an average of 1.0 aces per match in the last 52 weeks, consistent with her career average of 1.2.

Katerina Siniakova: Against top 50 players in the last 52 weeks, Katerina Siniakova holds a 13-14 record (48.1%). Throughout her career, she has competed against top 50 239 times, winning 94 (39.3%). Over the past 10 matches, she holds a 5-5 record. Over the past 52 weeks, Katerina Siniakova has posted a 36-22 record (62.1% win rate). Over her career at WTA level, Katerina Siniakova holds a record of 129-157 (45.1%) on hard, 62-55 (53.0%) on clay, and 30-29 (50.8%) on grass. In the last 52 weeks: 14-12 (53.8%) on hard, 4-4 (50.0%) on clay, and 4-5 (44.4%) on grass at WTA level. Katerina Siniakova has won five WTA tour-level titles (three on hard, one on clay, and one on grass). Katerina Siniakova serves an average of 1.9 aces per match in the last 52 weeks, consistent with her career average of 2.2.