Alycia Parks vs Sinja Kraus Head to Head Tennis Stats and Match Analysis

Alycia Parks and Sinja Kraus have not faced each other yet in our recorded match-ups. This head-to-head comparison analyzes their playing styles and recent performance statistics to provide insights into how a potential matchup might unfold.

Alycia Parks: Against opponents ranked outside top 100 players in the last 52 weeks, Alycia Parks holds a 9-14 record (39.1%). Throughout her career, she has competed against opponents ranked outside top 100 285 times, winning 152 (53.3%). Over the past 10 matches, she holds a 6-4 record. Over the past 52 weeks, Alycia Parks has posted a 23-32 record (41.8% win rate). Her last match was 3 weeks ago. Over her career at WTA level, Alycia Parks holds a record of 26-39 (40.0%) on hard, 9-15 (37.5%) on clay, and 2-7 (22.2%) on grass. In the last 52 weeks: 12-16 (42.9%) on hard, 3-6 (33.3%) on clay, and 0-1 on grass at WTA level. Alycia Parks has won one WTA tour-level title on hard. She has also won six titles at Challenger/ITF level (five on hard and one on grass). Alycia Parks is currently serving 6.4 aces per match in the last 52 weeks (55 matches), down from a career average of 7.0.

Sinja Kraus: Against top 100 players in the last 52 weeks, Sinja Kraus holds a 2-2 record (50.0%). Throughout her career, she has competed against top 100 15 times, winning 2 (13.3%). Over the past 10 matches, she holds a 7-3 record. Over the past 52 weeks, Sinja Kraus has posted a 52-27 record (65.8% win rate). Over her career at WTA level, Sinja Kraus holds a record of 2-2 (50.0%) on clay and 0-5 on hard. At Challenger/ITF level: 169-83 (67.1%) on clay, 50-53 (48.5%) on hard, and 1-1 (50.0%) on grass. In the last 52 weeks: 1-1 (50.0%) on clay and 0-1 on hard at WTA level. 40-15 (72.7%) on clay and 6-4 (60.0%) on hard at Challenger/ITF level. Sinja Kraus has won 13 titles at Challenger/ITF level (11 on clay and two on hard). Sinja Kraus serves an average of 1.9 aces per match in the last 52 weeks, consistent with her career average of 1.9.