Amanda Anisimova vs Maja Chwalinska Head to Head Tennis Stats and Match Analysis

Amanda Anisimova and Maja Chwalinska have not faced each other yet in our recorded match-ups. This head-to-head comparison analyzes their playing styles and recent performance statistics to provide insights into how a potential matchup might unfold.

Amanda Anisimova: Against top 50 players in the last 52 weeks, Amanda Anisimova holds a 22-12 record (64.7%). Throughout her career, she has competed against top 50 152 times, winning 79 (52.0%). Over the past 10 matches, she holds a 6-4 record. Over the past 52 weeks, Amanda Anisimova has posted a 36-14 record (72.0% win rate). Over her career at WTA level, Amanda Anisimova holds a record of 105-63 (62.5%) on hard, 41-26 (61.2%) on clay, and 24-11 (68.6%) on grass. In the last 52 weeks: 27-11 (71.1%) on hard, 7-2 (77.8%) on grass, and 2-1 (66.7%) on clay at WTA level. Amanda Anisimova has won four WTA tour-level titles (three on hard and one on clay). Amanda Anisimova is currently serving 3.7 aces per match in the last 52 weeks (50 matches), up from a career average of 2.5.

Maja Chwalinska: Against top 10 players in the last 52 weeks, Maja Chwalinska holds a 0-1 record (0.0%). Throughout her career, she has competed against top 10 1 times, winning 0 (0.0%). Over the past 10 matches, she holds a 9-1 record. Over the past 52 weeks, Maja Chwalinska has posted a 45-18 record (71.4% win rate). Her last match was 2 weeks ago. Over her career at WTA level, Maja Chwalinska holds a record of 8-3 (72.7%) on clay, 3-4 (42.9%) on hard, and 1-1 (50.0%) on grass. At Challenger/ITF level: 129-60 (68.3%) on clay, 66-39 (62.9%) on hard, and 3-2 (60.0%) on grass. In the last 52 weeks: 7-2 (77.8%) on clay and 2-1 (66.7%) on hard at WTA level. 24-10 (70.6%) on clay and 3-1 (75.0%) on hard at Challenger/ITF level. Maja Chwalinska has won 10 titles at Challenger/ITF level (eight on clay and two on hard). Maja Chwalinska serves an average of 0.6 aces per match in the last 52 weeks, consistent with her career average of 0.6.