Ann Li vs Jasmine Paolini Head to Head Tennis Stats and Match Analysis

Ann Li and Jasmine Paolini have not faced each other yet in our recorded match-ups. This head-to-head comparison analyzes their playing styles and recent performance statistics to provide insights into how a potential matchup might unfold.

Ann Li: Against top 10 players in the last 52 weeks, Ann Li holds a 0-3 record (0.0%). Throughout her career, she has competed against top 10 10 times, winning 1 (10.0%). Over the past 10 matches, she holds a 7-3 record. Over the past 52 weeks, Ann Li has posted a 33-25 record (56.9% win rate). Her last match was 2 months ago. Over her career at WTA level, Ann Li holds a record of 54-44 (55.1%) on hard, 12-10 (54.5%) on clay, and 6-9 (40.0%) on grass. In the last 52 weeks: 20-14 (58.8%) on hard, 9-7 (56.2%) on clay, and 2-3 (40.0%) on grass at WTA level. Ann Li has won two WTA tour-level titles both on hard. She has also won four titles at Challenger/ITF level (two on hard and two on clay). Ann Li is currently serving 4.3 aces per match in the last 52 weeks (58 matches), up from a career average of 2.9.

Jasmine Paolini: Against top 50 players in the last 52 weeks, Jasmine Paolini holds a 24-15 record (61.5%). Throughout her career, she has competed against top 50 152 times, winning 66 (43.4%). Jasmine Paolini has lost her last 4 matches. Over the past 10 matches, she holds a 5-5 record. Over the past 52 weeks, Jasmine Paolini has posted a 46-21 record (68.7% win rate). Her last match was 7 weeks ago. Over her career at WTA level, Jasmine Paolini holds a record of 96-75 (56.1%) on hard, 51-40 (56.0%) on clay, and 11-10 (52.4%) on grass. In the last 52 weeks: 27-15 (64.3%) on hard, 13-3 (81.2%) on clay, and 3-3 (50.0%) on grass at WTA level. Jasmine Paolini has won three WTA tour-level titles (two on hard and one on clay). She has also won 11 titles at Challenger/ITF level (nine on clay and two on hard). Jasmine Paolini serves an average of 1.3 aces per match in the last 52 weeks, consistent with her career average of 1.1.