Anna Blinkova vs Emerson Jones Head to Head Tennis Stats and Match Analysis

Anna Blinkova and Emerson Jones have not faced each other yet in our recorded match-ups. This head-to-head comparison analyzes their playing styles and recent performance statistics to provide insights into how a potential matchup might unfold.

Anna Blinkova: Against opponents ranked outside top 100 players in the last 52 weeks, Anna Blinkova holds a 10-12 record (45.5%). Throughout her career, she has competed against opponents ranked outside top 100 353 times, winning 228 (64.6%). Over the past 10 matches, she holds a 5-5 record. Over the past 52 weeks, Anna Blinkova has posted a 23-30 record (43.4% win rate). Over her career at WTA level, Anna Blinkova holds a record of 69-97 (41.6%) on hard, 20-35 (36.4%) on clay, and 15-19 (44.1%) on grass. In the last 52 weeks: 9-11 (45.0%) on hard, 2-4 (33.3%) on grass, and 1-4 (20.0%) on clay at WTA level. Anna Blinkova has won two WTA tour-level titles both on hard. She has also won four titles at Challenger/ITF level (all on hard). Anna Blinkova is currently serving 1.3 aces per match in the last 52 weeks (53 matches), down from a career average of 2.3.

Emerson Jones: Against opponents ranked outside top 100 players in the last 52 weeks, Emerson Jones holds a 39-14 record (73.6%). Throughout her career, she has competed against opponents ranked outside top 100 126 times, winning 87 (69.0%). Over the past 10 matches, she holds a 4-6 record. Over the past 52 weeks, Emerson Jones has posted a 41-20 record (67.2% win rate). Over her career at WTA level, Emerson Jones holds a record of 3-6 (33.3%) on hard and 0-1 on clay. At Challenger/ITF level: 68-29 (70.1%) on hard and 8-6 (57.1%) on grass. In the last 52 weeks: 2-4 (33.3%) on hard and 0-1 on clay at WTA level. 33-9 (78.6%) on hard and 0-2 on grass at Challenger/ITF level. Emerson Jones has won four titles at Challenger/ITF level (all on hard). Emerson Jones serves an average of 1.2 aces per match in the last 52 weeks, consistent with her career average of 1.2.