Daria Snigur vs Varvara Gracheva Head to Head Tennis Stats and Match Analysis

Daria Snigur and Varvara Gracheva have not faced each other yet in our recorded match-ups. This head-to-head comparison analyzes their playing styles and recent performance statistics to provide insights into how a potential matchup might unfold.

Daria Snigur: Against top 100 players in the last 52 weeks, Daria Snigur holds a 8-4 record (66.7%). Throughout her career, she has competed against top 100 37 times, winning 19 (51.4%). Over the past 10 matches, she holds a 6-4 record. Over the past 52 weeks, Daria Snigur has posted a 59-21 record (73.8% win rate). Over her career at WTA level, Daria Snigur holds a record of 6-8 (42.9%) on hard, 5-5 (50.0%) on grass, and 2-2 (50.0%) on clay. At Challenger/ITF level: 192-80 (70.6%) on hard, 12-9 (57.1%) on clay, and 12-8 (60.0%) on grass. In the last 52 weeks: 3-1 (75.0%) on hard, 2-2 (50.0%) on clay, and 2-1 (66.7%) on grass at WTA level. 42-13 (76.4%) on hard at Challenger/ITF level. Daria Snigur has won 13 titles at Challenger/ITF level (all on hard). Daria Snigur serves an average of 1.1 aces per match in the last 52 weeks, consistent with her career average of 0.8.

Varvara Gracheva: Against top 100 players in the last 52 weeks, Varvara Gracheva holds a 14-11 record (56.0%). Throughout her career, she has competed against top 100 190 times, winning 82 (43.2%). Varvara Gracheva has lost her last 3 matches. Over the past 10 matches, she holds a 6-4 record. Over the past 52 weeks, Varvara Gracheva has posted a 29-19 record (60.4% win rate). Her last match was 3 months ago. Over her career at WTA level, Varvara Gracheva holds a record of 58-75 (43.6%) on hard, 20-33 (37.7%) on clay, and 6-8 (42.9%) on grass. In the last 52 weeks: 9-12 (42.9%) on hard, 2-2 (50.0%) on grass, and 1-1 (50.0%) on clay at WTA level. Varvara Gracheva has won seven titles at Challenger/ITF level (all on clay). Varvara Gracheva is currently serving 2.8 aces per match in the last 52 weeks (48 matches), up from a career average of 1.9.