Ekaterine Gorgodze vs Jasmine Paolini Head to Head Tennis Stats and Match Analysis

Ekaterine Gorgodze and Jasmine Paolini have not faced each other yet in our recorded match-ups. This head-to-head comparison analyzes their playing styles and recent performance statistics to provide insights into how a potential matchup might unfold.

Ekaterine Gorgodze: Throughout her career, she has competed against top 20 2 times, winning 0 (0.0%). Ekaterine Gorgodze has lost her last 6 matches. Over the past 10 matches, she holds a 2-8 record. Over the past 52 weeks, Ekaterine Gorgodze has posted a 31-42 record (42.5% win rate). Over her career at WTA level, Ekaterine Gorgodze holds a record of 3-8 (27.3%) on clay, 0-3 on hard, and 0-1 on grass. At Challenger/ITF level: 257-176 (59.4%) on clay and 59-51 (53.6%) on hard. In the last 52 weeks: 0-1 on clay at WTA level. 23-25 (47.9%) on clay and 6-4 (60.0%) on hard at Challenger/ITF level. Ekaterine Gorgodze has won 13 titles at Challenger/ITF level (10 on clay and three on hard). Ekaterine Gorgodze serves an average of 0.8 aces per match in the last 52 weeks, consistent with her career average of 0.8.

Jasmine Paolini: Against opponents ranked outside top 100 players in the last 52 weeks, Jasmine Paolini holds a 9-2 record (81.8%). Throughout her career, she has competed against opponents ranked outside top 100 407 times, winning 260 (63.9%). Over the past 10 matches, she holds a 5-5 record. Over the past 52 weeks, Jasmine Paolini has posted a 33-23 record (58.9% win rate). Over her career at WTA level, Jasmine Paolini holds a record of 104-82 (55.9%) on hard, 54-44 (55.1%) on clay, and 11-10 (52.4%) on grass. In the last 52 weeks: 23-16 (59.0%) on hard, 3-4 (42.9%) on clay, and 3-3 (50.0%) on grass at WTA level. Jasmine Paolini has won three WTA tour-level titles (two on hard and one on clay). She has also won 11 titles at Challenger/ITF level (nine on clay and two on hard). Jasmine Paolini serves an average of 1.5 aces per match in the last 52 weeks, consistent with her career average of 1.1.