Jelena Ostapenko vs Lilli Tagger Head to Head Tennis Stats and Match Analysis

Jelena Ostapenko and Lilli Tagger have not faced each other yet in our recorded match-ups. This head-to-head comparison analyzes their playing styles and recent performance statistics to provide insights into how a potential matchup might unfold.

Jelena Ostapenko: Against top 100 players in the last 52 weeks, Jelena Ostapenko holds a 16-17 record (48.5%). Throughout her career, she has competed against top 100 439 times, winning 244 (55.6%). Over the past 10 matches, she holds a 7-3 record. Over the past 52 weeks, Jelena Ostapenko has posted a 20-21 record (48.8% win rate). Over her career at WTA level, Jelena Ostapenko holds a record of 172-141 (55.0%) on hard, 63-45 (58.3%) on clay, and 52-24 (68.4%) on grass. In the last 52 weeks: 11-14 (44.0%) on hard, 7-5 (58.3%) on clay, and 2-2 (50.0%) on grass at WTA level. Jelena Ostapenko has won nine WTA tour-level titles (five on hard, two on clay, and two on grass), including one Grand Slam title (on clay). Jelena Ostapenko serves an average of 3.4 aces per match in the last 52 weeks, consistent with her career average of 3.2.

Lilli Tagger: Against top 50 players in the last 52 weeks, Lilli Tagger holds a 1-4 record (20.0%). Throughout her career, she has competed against top 50 5 times, winning 1 (20.0%). Lilli Tagger has lost her last 3 matches. Over the past 10 matches, she holds a 4-6 record. Over the past 52 weeks, Lilli Tagger has posted a 36-18 record (66.7% win rate). Over her career at WTA level, Lilli Tagger holds a record of 6-3 (66.7%) on hard and 2-4 (33.3%) on clay. At Challenger/ITF level: 40-21 (65.6%) on clay and 18-8 (69.2%) on hard. In the last 52 weeks: 6-3 (66.7%) on hard and 2-4 (33.3%) on clay at WTA level. 15-5 (75.0%) on clay and 8-1 (88.9%) on hard at Challenger/ITF level. Lilli Tagger has won three titles at Challenger/ITF level (two on clay and one on hard). Lilli Tagger is currently serving 3.3 aces per match in the last 52 weeks (54 matches), up from a career average of 2.8.