Kaja Juvan vs Marketa Vondrousova Head to Head Tennis Stats and Match Analysis

Kaja Juvan and Marketa Vondrousova have met 1 time in professional competition, with Kaja Juvan leading 1-0. Their most recent encounter was in August 2020 at Palermo, where Kaja Juvan prevailed on clay court 1-6 7-5 6-4.

Kaja Juvan: Throughout her career, she has competed against top 50 38 times, winning 15 (39.5%). Over the past 10 matches, she holds a 7-3 record. Over the past 52 weeks, Kaja Juvan has posted a 46-18 record (71.9% win rate). Her last match was 6 weeks ago. Over her career at WTA level, Kaja Juvan holds a record of 24-29 (45.3%) on hard, 14-15 (48.3%) on clay, and 6-8 (42.9%) on grass. At Challenger/ITF level: 98-33 (74.8%) on clay and 25-15 (62.5%) on hard. In the last 52 weeks: 3-1 (75.0%) on clay, 1-3 (25.0%) on hard, and 0-1 on grass at WTA level. 18-5 (78.3%) on clay and 11-3 (78.6%) on hard at Challenger/ITF level. Kaja Juvan has won nine titles at Challenger/ITF level (eight on clay and one on hard). Kaja Juvan serves an average of 2.0 aces per match in the last 52 weeks, consistent with her career average of 2.1.

Marketa Vondrousova: Against opponents ranked outside top 100 players in the last 52 weeks, Marketa Vondrousova holds a 2-1 record (66.7%). Throughout her career, she has competed against opponents ranked outside top 100 151 times, winning 124 (82.1%). Over the past 10 matches, she holds a 6-4 record. Over the past 52 weeks, Marketa Vondrousova has posted a 18-10 record (64.3% win rate). Her last match was 2 months ago. Over her career at WTA level, Marketa Vondrousova holds a record of 99-62 (61.5%) on hard, 46-27 (63.0%) on clay, and 18-14 (56.2%) on grass. In the last 52 weeks: 10-8 (55.6%) on hard, 6-1 (85.7%) on grass, and 2-1 (66.7%) on clay at WTA level. Marketa Vondrousova has won three WTA tour-level titles (two on grass and one on hard), including one Grand Slam title (on grass). Marketa Vondrousova is currently serving 4.4 aces per match in the last 52 weeks (28 matches), up from a career average of 2.5.