Holger Rune vs Vitaliy Sachko Head to Head Tennis Stats and Match Analysis

Holger Rune and Vitaliy Sachko have met 2 times in professional competition, with the series tied at 1-1. Their most recent encounter was in July 2021 at Perugia Challenger, where Vitaliy Sachko prevailed on clay court 6-3 7-6(4).

Holger Rune: Against opponents ranked outside top 100 players in the last 52 weeks, Holger Rune holds a 1-4 record (20.0%). Throughout his career, he has competed against opponents ranked outside top 100 196 times, winning 139 (70.9%). Over the past 10 matches, he holds a 7-3 record. Over the past 52 weeks, Holger Rune has posted a 14-8 record (63.6% win rate). His last match was 8 months ago. Over his career at ATP level, Holger Rune holds a record of 100-58 (63.3%) on hard, 54-33 (62.1%) on clay, and 12-9 (57.1%) on grass. In the last 52 weeks: 13-6 (68.4%) on hard and 0-1 on grass at ATP level. Holger Rune has won five ATP tour-level titles (three on clay and two on hard). He has also won eight titles at Challenger/ITF level (seven on clay and one on hard). Holger Rune is currently serving 7.2 aces per match in the last 52 weeks (22 matches), up from a career average of 4.7.

Vitaliy Sachko: Against top 100 players in the last 52 weeks, Vitaliy Sachko holds a 5-3 record (62.5%). Throughout his career, he has competed against top 100 36 times, winning 10 (27.8%). Over the past 10 matches, he holds a 6-4 record. Over the past 52 weeks, Vitaliy Sachko has posted a 26-31 record (45.6% win rate). Over his career at ATP level, Vitaliy Sachko holds a record of 3-4 (42.9%) on hard and 0-4 on clay. At Challenger/ITF level: 152-132 (53.5%) on clay and 96-74 (56.5%) on hard. In the last 52 weeks: 3-1 (75.0%) on hard and 0-1 on clay at ATP level. 16-12 (57.1%) on clay and 2-6 (25.0%) on hard at Challenger/ITF level. Vitaliy Sachko has won three titles at Challenger/ITF level (two on clay and one on hard). Vitaliy Sachko is currently serving 3.7 aces per match in the last 52 weeks (57 matches), up from a career average of 3.2.