Varvara Gracheva vs Veronika Kudermetova Head to Head Tennis Stats and Match Analysis

Varvara Gracheva and Veronika Kudermetova have met 4 times in professional competition, with Veronika Kudermetova leading 3-1. Their most recent encounter was in August 2025 at Cincinnati, where Veronika Kudermetova prevailed on hard court 6-1 6-2.

Varvara Gracheva: Against top 50 players in the last 52 weeks, Varvara Gracheva holds a 6-12 record (33.3%). Throughout her career, she has competed against top 50 84 times, winning 26 (31.0%). Over the past 10 matches, she holds a 7-3 record. Over the past 52 weeks, Varvara Gracheva has posted a 33-27 record (55.0% win rate). Her last match was 2 months ago. Over her career at WTA level, Varvara Gracheva holds a record of 54-68 (44.3%) on hard, 20-33 (37.7%) on clay, and 6-8 (42.9%) on grass. In the last 52 weeks: 8-11 (42.1%) on hard, 4-6 (40.0%) on clay, and 2-2 (50.0%) on grass at WTA level. Varvara Gracheva has won seven titles at Challenger/ITF level (all on clay). Varvara Gracheva serves an average of 2.3 aces per match in the last 52 weeks, consistent with her career average of 1.9.

Veronika Kudermetova: Against top 100 players in the last 52 weeks, Veronika Kudermetova holds a 24-21 record (53.3%). Throughout her career, she has competed against top 100 302 times, winning 158 (52.3%). Over the past 10 matches, she holds a 4-6 record. Over the past 52 weeks, Veronika Kudermetova has posted a 35-25 record (58.3% win rate). Her last match was 2 months ago. Over her career at WTA level, Veronika Kudermetova holds a record of 118-98 (54.6%) on hard, 52-34 (60.5%) on clay, and 25-18 (58.1%) on grass. In the last 52 weeks: 17-15 (53.1%) on hard, 7-5 (58.3%) on clay, and 3-3 (50.0%) on grass at WTA level. Veronika Kudermetova has won two WTA tour-level titles (one on hard and one on clay). She has also won five titles at Challenger/ITF level (three on hard and one on clay). Veronika Kudermetova serves an average of 4.8 aces per match in the last 52 weeks, consistent with her career average of 4.9.